After I installed 126.96.36.199, I had a problem with the VMWare VCenter client where it would not connect. A colleague of mine that was having the same problem indicated I needed to do this command:
netsh winsock reset
and then reboot.
Upon reboot, I got the warning shown below. He indicated to uninstall Tectia and reinstalled without transparent TCP tunneling, which I did. But I continue to get this warning at start up.
So now I suspect there is a registry key that needs to be deleted.
Does anyone know the solution to this problem of the warning popping up all the time?
Thanks in advanced for your help.
asked May 31 '11 at 16:20
Run the command to install the SSH Capture component from command line:
If after uninstallation you still get the error message, I believe the winsock2 may be corrupted. This is not an issue we have seen before. I suggest doing the following:
File Locations in Windows: http://www.tectia.com/manuals/client-user/61/clientgs-fileswin.html
Registry Keys in Windows: http://www.tectia.com/manuals/client-user/61/csc-win-registrykeys.html
Reboot the machine.
If the error occurs again, I suggest turning off your antivirus and reset the winsock2 configuration (this however can cause other issues with software that uses the winsock2 stack):
Manual steps to recover from Winsock2 corruption
To repair Winsock if you have Windows XP Service Pack 2 (SP2) installed, type netsh winsock reset at the command prompt, and then press ENTER.
Note Restart the computer after you run this command. Additionally, for computers that are running Windows XP SP2, there is a new netsh command that can rebuild the Winsock key. For more information, visit the following Web site: http://technet.microsoft.com/en-us/library/bb457156.aspx
Warning Programs that access or monitor the Internet such as antivirus, firewall, or proxy clients may be negatively affected when you run the netsh winsock reset command. If you have a program that no longer functions correctly after you use this resolution, reinstall the program to restore functionality.
answered Jul 06 '11 at 09:15